RANKING PART1



INTRODUCTION:

Ranking and order is an important topic of banking question paper under logical reasoning section, it involves an arrangement of position or ranks of an object or a person either from left to right or top to bottom. It involves the usage of a few tips and tricks learned in the seating arrangement.

It involves the usage of a few tips and tricks learned in the seating arrangement. Usage of simple shortcut tricks is sufficient to crack ranking and order in a few.


To know more about bank exams, check at the linked article.

Attending these questions helps in boosting the reasoning ability and also the score in the exam. 

Often one can find the order and ranking.

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Rule #1.

The total number of a person/objects in a group or class is equal to one less than the sum of the positions of the same person from both the ends (either right and left or top and bottom). Since the same person is counted twice in the sum, the final answer is one less than the total sum.

  1. Total number of objects/persons

= [(sum of positions of the same person/object from both sides) – 1]

Example 1:

In a row of persons, the position of Saket from the left side of the row is 27th and position of Saket from the right side of the row is 34th. Find the total number of students in the row?

  1. 60
  2. 61
  3. 62
  4. 59

Solution:

Total number of students

= (Position of Saket from left + Position of Saket from right) -1

Total number of students = (27 + 34) – 1 = 61 – 1 = 60.

Hence the correct answer is option A in the banking question paper.



Rule#2

The total number of person/object in a group is the sum of before or after the given person in a row and the position of the same person from the other side.

Total no. of persons/objects = No. of persons/objects before or after the given person in a row + Position of the same person from the other side.



Example 2:

In a row of persons, the position of Aparna Nair from the left side of the row is 27th and there are 5 persons after her in the row. Find the total no. of persons in the row?

Solution:

No. of persons in the row = Position of Aparna from left + No. of persons after Aparna

⇒ Total no. of persons = 27 + 5 = 32


Rule#3

If the positions of two objects/persons are given from the opposite ends and also the total number of persons/objects, then the problem can be addressed in two different ways to determine the number of persons between these two persons/objects.


Case 1:

Overlapping:

The total number of objects or persons in a group is always lesser than the addition of the position of two objects or persons from ends.

Example 3:

The number of objects between two different persons = Total number of books – (Sum of positions of two different persons from opposite sides)

There are 24 students in dance class, and the teacher is planning for an arrangement of students on stage. Sampratha is 9th from the left side of the row and Supreetha is 22nd from the right side of the row. Find the number of dancers standing between the sisters Sampratha and Supreetha?

A.4

B.5

C.6

D.7

Solution:

Adding the position of Sampratha and Supreetha we get:

= 9 + 22 = 31

The result ‘31’ is greater than the total number of students in a dance class.

Therefore the number of dancers standing between the sisters will be = [(Position of Sampratha from left + Position of Supreetha from right) – Total number of dancers – 2]

The number of dancers between sampratha an supreetha

= (9+22) – 24 – 2 = 31 – 24 – 2 = 5.

Hence the correct answer is option B.


Case 2:

Non – overlapping:

The total number of objects or persons in a group is always greater than the addition of the position of two objects or persons from ends.

Example 4:

There are 64 history books arranged in a row at central library Bangalore. Ancient history is 25th from the left side of the row and Middivel history is 30th from the right side of the row. What is the total number of books between Ancient and Middivel history?

A.6

B.7

C.8

D.9

Solution:

Adding the position of ancient and midlevel history books, we get:

Ancient histroy+ Middivel history = 25 + 30 = 55

Hence the number ‘55’ should be less than the total number of books.

∴ The number of books between ancient and midlevel history = Total number of books – (Place value of Ancient history book from left + Place value of Middivel history from right)

The number of books between ancient and midlevel history = 64 – (25+30) = 64 – 55 = 9

Hence the correct is option D.


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